Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 15 - Exercises and Problems - Page 280: 45


Please see the work below.

Work Step by Step

We know that $P=\frac{F}{A}$ $\implies P=\frac{mg}{\pi r^2}$ This can be rearranged as $m=\frac{\pi r^2P}{g}$ We plug in the known values to obtain: $m=\frac{\pi (\frac{0.45}{2})^2(500,000)}{9.8}$ $m=8100Kg$
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