Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 15 - Exercises and Problems: 33

Answer

Please see the work below.

Work Step by Step

We know that $A_1v_1=A_2v_2$ This can be rearranged as: $v_2=(\frac{A_1}{A_2})v_1$ $\implies v_2=(\frac{d_1}{d_2})^2v_1$ We plug in the known values to obtain: $v_2=(\frac{2.5}{2.0})^2(1.8)$ $v_2=2.8\frac{m}{s}$
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