## Essential University Physics: Volume 1 (3rd Edition)

a) $1.91\ m/s$ b) $30.6\ m/s$
We know that the velocity is equal to the flow rate divided by the cross sectional area times the density of water. Thus, we find: a) $v = \frac{15}{\pi(.05)^2(1000)} = 1.91\ m/s$ b) We do the same process to find: $v = \frac{15}{\pi(.0125)^2(1000)} = 30.6\ m/s$