Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 15 - Exercises and Problems - Page 280: 38


Please see the work below.

Work Step by Step

We can find the area as $A=\frac{F}{A}$ We plug in the known values to obtain: $A=\frac{(120)(9.8)}{4700}$ $A=0.25m^2$
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