## Essential University Physics: Volume 1 (3rd Edition)

a) $1.8 \times10^4 m^3/s$ b) $1.5 \ m/s$
a) We find the flow rate, which we will call r, as follows: $r = \frac{1.8\times10^7}{10^3} = 1.8 \times10^4 m^3/s$ b) We know that the velocity is given by the area divided by the flow rate. Thus, we find: $v = \frac{1.8 \times10^4 m^3/s}{12 \times 10^3 \ m^2} = 1.5 \ m/s$