Answer
.20 meters
Work Step by Step
We simplify the equation for energy to solve for the Amplitude and find:
$A = \sqrt{\frac{2E}{4\pi^2f^2m}}$
$A = \sqrt{\frac{2(.51)}{4\pi^2(1.2)^2(.45)}}=\fbox{.20 meters}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 13 - Exercises and Problems - Page 238: 34
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