Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 13 - Exercises and Problems: 32

Answer

a) 10 Hz b) 62.8 rads/s

Work Step by Step

We find: a) $ f= \frac{\omega}{t}=\frac{600}{60}=\fbox{10 Hz}$ b) We use the equation for omega: $\omega = 2\pi f = 2\pi (10) = \fbox{62.8 rads/s}$
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