## Essential University Physics: Volume 1 (3rd Edition)

We find: a) $\omega = \frac{a_{max}}{v_{max}}=\frac{3.1}{1.4}=\fbox{2.2 seconds}$ b) $T = \frac{2\pi }{\omega} = \frac{2\pi }{2.2}= \fbox {2.8 seconds}$ c) We simplify the equation for the maximum possible speed to find: $A = \frac{v_{max}}{\omega}= \frac{1.4}{2.2}=\fbox{.63 meters}$