Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 13 - Exercises and Problems - Page 238: 29

Answer

1.21 seconds

Work Step by Step

We use the equation for the period of a pendulum to find: $T = 2\pi\sqrt{\frac{L}{g}}=2\pi\sqrt{\frac{1.45 \ m}{9.81\ m/s^2}}=2.4156\ s$ The tick occurs every half period, which is $ \frac{2.4156\ s}{2} = \fbox{1.21 seconds}$
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