Answer
$\frac{1}{3}Ma^2$
Work Step by Step
We use the parallel axis theorem to obtain:
$I = (\frac{1}{2}a)^2M + \frac{1}{12}Ma^2 = \frac{4}{12}Ma^2=\frac{1}{3}Ma^2$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 10 - Exercises and Problems - Page 185: 51
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