## Essential University Physics: Volume 1 (3rd Edition)

We know that $t=\frac{x}{v}=\frac{150}{25}=6s=\frac{6}{60}=0.1m$ We can find the angular frequency of flagellum as $f=\frac{\omega}{2\pi}=\frac{600}{2\pi}=95rps=5700rpm$ We can find the number of revolutions as $N=ft=(5700)(0.1)=570revolutions$