Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 10 - Exercises and Problems: 46

Answer

Please see the work below.

Work Step by Step

We know that the average speed is given as $\omega_{avg}=\frac{\omega_i+\omega_f}{2}$ We plug in the known values to obtain: $\omega_{avg}=\frac{5800+0}{2}=2900rpm$ Now we can we find the number of revolutions as $N=(2900rpm)(\frac{2s}{60minute})=97revolutions$
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