Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 10 - Exercises and Problems: 43

Answer

a) 1.04 radians per second b) 1.089 meters per second

Work Step by Step

a) We first find the frequency: $ f = \frac{20}{60}=.33\ Hz$ We use this to find the average angular velocity: $\bar{\omega}=\frac{\omega_f+\omega_0}{2} = \frac{2\pi f+\omega_0}{2} = \frac{2\pi \times .33+0}{2}=\fbox{1.04 radians per second}$ b) We now find the velocity: $v=\omega r = (1.04)(1.05)=\fbox{1.089 meters per second}$
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