Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 10 - Exercises and Problems - Page 185: 33

Answer

20 minutes

Work Step by Step

We find: $\alpha = \frac{\tau}{I}=\frac{rF}{\frac{1}{2}mr^2}=\frac{.205\times34,000}{.5(7.7\times10^4)(2.4^2)}=.0314\ rads/s^2$ Converting the rotation speed to radians per second, we find: $37.699/.0314=1200\ s =\fbox{20 minutes}$
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