Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 10 - Exercises and Problems - Page 184: 26


Please see the work below.

Work Step by Step

We can find the moment of inertia of the shaft as $I=(\frac{1}{2})MR^2$ We plug in the known values to obtain: $I=(\frac{1}{2})(6800)(0.85/2)^2$ $I=614 \ kg.m^2$
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