#### Answer

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#### Work Step by Step

We can find the moment of inertia of the shaft as
$I=(\frac{1}{2})MR^2$
We plug in the known values to obtain:
$I=(\frac{1}{2})(6800)(0.85/2)^2$
$I=614 \ kg.m^2$

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Published by
Pearson

ISBN 10:
0321993721

ISBN 13:
978-0-32199-372-4

Please see the work below.

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