## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 10 - Exercises and Problems - Page 184: 19

#### Answer

a) .156 revolutions b) .07 radians per second

#### Work Step by Step

a) We use the equation for the change in theta to find: $\Delta \theta = \omega_0t + \frac{1}{2}\alpha t^2 \\ \Delta \theta = \frac{1}{2}(.01)(14^2)=.98 \ rads = \fbox{.156 revolutions}$ b) We find: $\bar{\omega}=\frac{\theta}{t}=\frac{.98}{14}=\fbox{.07 radians per second}$

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