Answer
a) .156 revolutions
b) .07 radians per second
Work Step by Step
a) We use the equation for the change in theta to find:
$\Delta \theta = \omega_0t + \frac{1}{2}\alpha t^2 \\ \Delta \theta = \frac{1}{2}(.01)(14^2)=.98 \ rads = \fbox{.156 revolutions}$
b) We find:
$\bar{\omega}=\frac{\theta}{t}=\frac{.98}{14}=\fbox{.07 radians per second}$
