## Essential University Physics: Volume 1 (3rd Edition)

We know that the angular speed is given as $\omega=2\pi f$ We plug in the known values to obtain: $\omega=2(3.1416)(\frac{3500}{60})=366.5\frac{rad}{s}$ Now we can find the required linear speed as $v=r\omega$ We plug in the known values to obtain: $v=(0.25/2)(366.5)=46\frac{m}{s}$