Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 10 - Exercises and Problems: 22

Answer

Please see the work below.

Work Step by Step

(a) We know that $\tau=rFsin(\theta)$ This can be rearranged as: $F=\frac{\tau}{rsin{\theta}}$ We plug in the known values to obtain: $F=\frac{35}{(0.24)sin(90)}=150N$ (b) As $F=\frac{\tau}{rsin(\theta)}$ We plug in the known values to obtain: $F=\frac{35}{(0.24)sin(110)}=160N$
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