Answer
Please see the work below.
Work Step by Step
(a) We know that
$\tau=rFsin(\theta)$
This can be rearranged as:
$F=\frac{\tau}{rsin{\theta}}$
We plug in the known values to obtain:
$F=\frac{35}{(0.24)sin(90)}=150N$
(b) As $F=\frac{\tau}{rsin(\theta)}$
We plug in the known values to obtain:
$F=\frac{35}{(0.24)sin(110)}=160N$
