Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 10 - Exercises and Problems: 24

Answer

Please see the work below.

Work Step by Step

We know that $\tau=Frsin(\theta)$ $\implies \tau=mgrsin(\theta)$ We plug in the known values to obtain: $\tau=(0.025)(9.8)(0.32)sin(90-24)=0.072N.m$
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