College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 260: 9

Answer

$1500$

Work Step by Step

$r=0.325m$ Distance $=3km=3000m$ Now, $Circumference=2\times pi\times r=2\times pi\times 0.325=2m$ Hence, number of revolutions =$\frac{3000}{2}=1500rev$
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