College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 260: 5

Answer

a). $105^{\circ}=105\times\frac{pi}{180} rad=1.83 rad$ Also, $105^{\circ}=\frac{105}{360}rev=0.29rev$ b). $1.8rad=1.8\times\frac{180}{pi}=103^{\circ}$ Also, $1.8rad=103^{\circ}=\frac{103}{360}rev=0.29rev$ c). $\frac{5}{7}rev=\frac{5}{7}\times360^{\circ}=257^{\circ}$ Also,$=257\times\frac{pi}{180}=4.49rad$

Work Step by Step

a). $105^{\circ}=105\times\frac{pi}{180} rad=1.83 rad$ Also, $105^{\circ}=\frac{105}{360}rev=0.29rev$ b). $1.8rad=1.8\times\frac{180}{pi}=103^{\circ}$ Also, $1.8rad=103^{\circ}=\frac{103}{360}rev=0.29rev$ c). $\frac{5}{7}rev=\frac{5}{7}\times360^{\circ}=257^{\circ}$ Also,$=257\times\frac{pi}{180}=4.49rad$
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