College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 260: 6

Answer

$192m$

Work Step by Step

$S=r\theta$ $1.5^{\circ}=1.5\times\frac{pi}{180}rad=0.026rad$ Also, $S=5.0m$ Thus, $r=\frac{S}{\theta}=\frac{5}{0.026}=192m$
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