College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 260: 8

Answer

$6.5cm$

Work Step by Step

Second hand completes 1 cycle in 1 min. So it rotates $30\times 2\times pi=60pi \,\,rad$ Length of second hand =0.35m, distance travelled =$0.35\times 60pi=66m$ Minute hand completes 1 cycle in 1 min. In 30 mins, it rotates $180^{\circ}=pi \,\,rad$. Length of minute hand is $0.3m$. So distance travelled by minute hand $=pi\times0.3=0.94m$ Hour hand rotates $15^{\circ}=\frac{pi}{12} rad$ in 30 mins. Length of hour hand is 0.25m. So, the distance travelled by hour hand =$0.25\times\frac{pi}{12} =0.065m=6.5cm$
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