College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 7 - Circular Motion and Gravitation - Learning Path Questions and Exercises - Exercises - Page 260: 10

Answer

$60\,\,rad$

Work Step by Step

Outer rims will cover same distance. Larger wheel turns 4 revolutions. i.e. distance is $4\times2pi\times0.6=4.8pi \,m=15m$ Angle turned by small wheel =$\frac{15}{0.25}=60 rad$
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