Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 136: 34

a). $0.77m/s^{2}$ b). $5.44m$

a). The force is same. $m_{a}a_{a}=m_{b}a_{b}$ $a_{b}=\frac{m_{a}a_{a}}{m_{b}}=\frac{50\times0.92}{60}=0.77m/s^{2}$ b). Relative acceleration =$0.92+0.77=1.69m/s^{2}$ $t=\sqrt \frac{2d}{a}=\sqrt \frac{2\times10}{1.69}=3.44s$ So, $d=\frac{at^{2}}{2}=\frac{0.92\times3.44^{2}}{2}=5.44m$