College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 136: 23

Answer

$2.40\,m/s^{2}$

Work Step by Step

According to Newton's second law $a=\frac{F_{net}}{m}=\frac{F-f}{m}$ $=\frac{300\,N-120\,N}{75.0\,kg}=2.40\,m/s^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.