## College Physics (7th Edition)

$a).$ Angle of the ball should be backwards from vertical. $b).$ $0.51m/s^{2}$
a). The angle of the ball is backward from vertical. As the RV starts moving or accelerating forwards, the ball moves backward due to inertia. b). The ball makes $3^{\circ}$ with vertical. Thus, by both vertical and horizontal components, $Tsin\theta=ma$ $Tcos\theta=mg$ or, $tan\theta=\frac{a}{g}$ $a=gtan\theta=9.8\times tan3^{\circ}=0.51m/s^{2}$