#### Answer

$(-2.6\,N)\hat{x}+(1.5\,N)\hat{y}$

#### Work Step by Step

$\vec{a}=-\hat{x}(a\cos\theta)+\hat{y}(a\sin\theta)$$=(-1.5\,m/s^{2}\times\cos30^{\circ})\hat{x}+(1.5\,m/s^{2}\times\sin30^{\circ})\hat{y}$$=(-1.3\,m/s^{2})\hat{x}+(0.75\,m/s^{2})\hat{y}$
$\vec{F}=m\vec{a}=(2.0\,kg)[(-1.3\,m/s^{2})\hat{x}+(0.75\,m/s^{2})\hat{y}]$
$=(-2.6\,N)\hat{x}+(1.5\,N)\hat{y}$