College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 136: 29



Work Step by Step

$\vec{a}=-\hat{x}(a\cos\theta)+\hat{y}(a\sin\theta)$$=(-1.5\,m/s^{2}\times\cos30^{\circ})\hat{x}+(1.5\,m/s^{2}\times\sin30^{\circ})\hat{y}$$=(-1.3\,m/s^{2})\hat{x}+(0.75\,m/s^{2})\hat{y}$ $\vec{F}=m\vec{a}=(2.0\,kg)[(-1.3\,m/s^{2})\hat{x}+(0.75\,m/s^{2})\hat{y}]$ $=(-2.6\,N)\hat{x}+(1.5\,N)\hat{y}$
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