College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 27 - Quantum Physics - Learning Path Questions and Exercises - Exercises - Page 935: 17

Answer

longest possible wavelength of light is approximately $\lambda=355 nm$

Work Step by Step

metal has a work function $\phi_{0}=3.50eV$=$5.6\times10^{-19}J$ since $ 1 eV$ is equal to $1.6\times10^{-19}J$ so $3.50eV$ will be equal to $3.50\times1.6\times10^{-19}J=5.6\times10^{-19}J$ work function is threshold energy for which electron is just emitted from the surface with zero kinetic energy. from equation 27.8 cutoff , threshold or minimum frequency $ f_{0}=\frac{\phi_{0}}{h}$ putting the values $\phi_{0}=5.6\times10^{-19}J$ and $h=6.63\times10^{-34} J.s$ $ f_{0}=\frac{5.6\times10^{-19}J}{6.63\times10^{-34} J.s}=0.8446\times10^{15}/s$ $ f_{0}=8.446\times10^{14}Hz$ corresponding longest wavelength will be $\lambda=\frac{c}{f}=\frac {3\times10^{8}m/s}{8.446\times10^{14}Hz}=0.355197\times10^{-6}m$ $\lambda=355.197\times10^{-9}m=355.197nm$ so longest possible wavelength is approximately $\lambda=355 nm$
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