Answer
Stopping voltage will remain same at $5.0V$
Work Step by Step
Stopping potential is voltage corresponding to maximum kinetic energy of photoelectrons emitted.
$K_{max}=eV_{0}$, where $K_{max}$ is maximum kinetic energy,$e$ is charge on electron and $V_{0}$, is stooping potential.
From equation 27.7
$hf= K_{max} + \phi_{0}$
$K_{max} =hf-\phi_{0}$,
putting the value of $K_{max}$ in this equation we will get
$eV_{0} =hf-\phi_{0}$,
so stopping potential only depends upon work function of surface and frequency of incident light. it does not depend upon the intensity of incident light.
so if intensity of light is tripled stopping voltage will not change.