College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 27 - Quantum Physics - Learning Path Questions and Exercises - Exercises - Page 935: 16

Answer

Stopping voltage will remain same at $5.0V$

Work Step by Step

Stopping potential is voltage corresponding to maximum kinetic energy of photoelectrons emitted. $K_{max}=eV_{0}$, where $K_{max}$ is maximum kinetic energy,$e$ is charge on electron and $V_{0}$, is stooping potential. From equation 27.7 $hf= K_{max} + \phi_{0}$ $K_{max} =hf-\phi_{0}$, putting the value of $K_{max}$ in this equation we will get $eV_{0} =hf-\phi_{0}$, so stopping potential only depends upon work function of surface and frequency of incident light. it does not depend upon the intensity of incident light. so if intensity of light is tripled stopping voltage will not change.
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