Answer
Wavelength= 306 nm. This light belongs to the UV region.
Work Step by Step
Recall the equation E= hν = hc/λ.
Then, wavelength(λ) = $\frac{hc}{E}$ where h is the Planck's constant, c is the speed of light and E the energy of the photon.
Substituting the values,
We have λ= $\frac{(6.626×10^{-34}Js)(3.00×10^{8}m/s)}{6.50×10^{-19}J}$=$
3.06×10^{-7}m$= 306 nm
Referring to the electromagnetic spectrum we can find out that the light with this wavelength is in the ultra violet region.
