## College Physics (7th Edition)

Maximum equivalent capacitance= $6.5\,\mu F$ Minimum equivalent capacitance= $0.67\,\mu F$
Maximum equivalent capacitance is obtained when the capacitors are connected in parallel. In that case, the equivalent capacitance $C_{p}=C_{1}+C_{2}+C_{3}=1.5\,\mu F+2.0\,\mu F+3.0\,\mu F$ $=6.5\,\mu F$ When the connection is in series, the equivalent capacitance is minimum which is equal to $C_{s}=\frac{1}{\frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}}}=\frac{1}{\frac{1}{1.5\,\mu F}+\frac{1}{2.0\,\mu F}+\frac{1}{3.0\,\mu F}}=0.67\,\mu F$