College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 16 - Electric Potential, Energy, and Capacitance - Learning Path Questions and Exercises - Exercises - Page 594: 55


Maximum equivalent capacitance= $6.5\,\mu F$ Minimum equivalent capacitance= $0.67\,\mu F$

Work Step by Step

Maximum equivalent capacitance is obtained when the capacitors are connected in parallel. In that case, the equivalent capacitance $C_{p}=C_{1}+C_{2}+C_{3}=1.5\,\mu F+2.0\,\mu F+3.0\,\mu F$ $=6.5\,\mu F$ When the connection is in series, the equivalent capacitance is minimum which is equal to $C_{s}=\frac{1}{\frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}}}=\frac{1}{\frac{1}{1.5\,\mu F}+\frac{1}{2.0\,\mu F}+\frac{1}{3.0\,\mu F}}=0.67\,\mu F$
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