Chapter 16 - Electric Potential, Energy, and Capacitance - Learning Path Questions and Exercises - Exercises - Page 594: 49

(a) $0.24\,\mu F$ (b) $1.0\,\mu F$

(a) $\frac{1}{C_{s}}=\frac{1}{C_{1}}+\frac{1}{C_{2}}=\frac{C_{2}+C_{1}}{C_{1}C_{2}}$ $\implies C_{s}=\frac{C_{1}C_{2}}{C_{2}+C_{1}}=\frac{0.40\,\mu F\times0.60\,\mu F}{0.40\,\mu F+0.60\,\mu F}=0.24\,\mu F$ (b) $C_{p}=C_{1}+C_{2}=0.40\,\mu F+0.60\,\mu F=1.0\,\mu F$