College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 16 - Electric Potential, Energy, and Capacitance - Learning Path Questions and Exercises - Exercises - Page 594: 44

Answer

3

Work Step by Step

The expression is $C=\kappa C_{0}$ where $C$ is the capacitance after the dielectric material is added, $C_{0}$ is the capacitance when the air is in between the plates and $\kappa$ is the dielectric constant of the material. $\implies \kappa=\frac{C}{C_{0}}=\frac{150\,pF}{50\,pF}=3$
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