College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 16 - Electric Potential, Energy, and Capacitance - Learning Path Questions and Exercises - Exercises - Page 594: 50

Answer

For series connection: C=$2.0\,\mu F$ For parallel connection: C=$0.5\,\mu F$

Work Step by Step

For series connection: $\frac{1}{C_{equivalent}}=\frac{1}{C}+\frac{1}{C}=\frac{2}{C}=\frac{1}{1.0\times10^{-6}\,F}$ $\implies C=2(1.0\times10^{-6}\,F)=2.0\times10^{-6}\,F=2.0\,\mu F$ For parallel connection: $C_{equivalent}=C+C=2C=1.0\,\mu F$ $\implies C=\frac{1.0\,\mu F}{2}=0.5\,\mu F$
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