Answer
For series connection: C=$2.0\,\mu F$
For parallel connection: C=$0.5\,\mu F$
Work Step by Step
For series connection: $\frac{1}{C_{equivalent}}=\frac{1}{C}+\frac{1}{C}=\frac{2}{C}=\frac{1}{1.0\times10^{-6}\,F}$
$\implies C=2(1.0\times10^{-6}\,F)=2.0\times10^{-6}\,F=2.0\,\mu F$
For parallel connection: $C_{equivalent}=C+C=2C=1.0\,\mu F$
$\implies C=\frac{1.0\,\mu F}{2}=0.5\,\mu F$