College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 16 - Electric Potential, Energy, and Capacitance - Learning Path Questions and Exercises - Exercises - Page 594: 45


(a) $3.1\times10^{-9}\,C$ (b) $3.7\times10^{-8}\,J$

Work Step by Step

(a) Charge $q=CV=(\kappa C_{0})V=(2.6\times50\times10^{-12}\,F)24\,V$ $=3.1\times10^{-9}\,C$ (b) Energy $U=\frac{1}{2}CV^{2}=\frac{1}{2}\times(\kappa C_{0})\times V^{2}$ $=\frac{1}{2}\times2.6\times50\times10^{-12}\,F\times(24\,V)^{2}=3.7\times10^{-8}\,J$
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