## College Physics (7th Edition)

Published by Pearson

# Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 383: 29

#### Answer

$33.4lb/in^{2}$

#### Work Step by Step

By ideal gas law for fixed number of moles and volume : $\frac{P}{T}=constant$ $T_{1}=61F=289.61K$, $P_{1}=30+14.7=44.7psi$ $T_{2}=100F=310.93K$ Now, $\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$ or, $\frac{44.7}{289.61}=\frac{P_{2}}{310.93}$ or, $P_{2}=48.1psi$ Thus, gauge pressure =$48.1-14.7=33.4lb/in^{2}$

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