Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 383: 14

a). (2) $T_{C}=0$, b). y-intercept = $F=32$ c). slope = $0.555$ and y-intercept $=-17.78$

a). (2) $T_{C}=0$, since we want to find y-intercept, x value has to be zero, i.e. $T_{C}=0$. b). $C=\frac{F-32}{1.8}$ $F=1.8C+32$ we get y-intercept, when C=0, i.e. $F=32$ c). if the graph had been plotted the other way , i.e. $C=\frac{F-32}{1.8}$ Slope = $0.555$ and y-intercept =$\frac{0-32}{1.8}=-17.78$