College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 383: 20


a). $(2)$ decreased, b). $166.5^{\circ}C$

Work Step by Step

a). (2) decreased Since, $PV=nRT$, in constant volume thermometer if pressure decreases then temperature will also decrease. b). P=1000Pa, T=$20^{\circ}C=293K$ Final pressure = 1500Pa. Pressure increased 1.5 times so temperature will also increase 1.5 times. Final temperature = $1.5\times 293=439.5K=166.5^{\circ}C$
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