College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 383: 24

Answer

$1.71247\times10^{23}$

Work Step by Step

T=300K, P=1atm=$1.01325\times10^{5}Pa$ By ideal gas law :- PV = NRT So, N=$\frac{101325\times0.007}{300\times8.314}=0.284$ So, n=$N\times6.022\times10^{23}=1.71247\times10^{23}$
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