College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Exercises - Page 383: 27

Answer

2.5 atm

Work Step by Step

Using Ideal gas law : $NR/V=P/T=3/303$ For $T=-20^{\circ}C=253K$ $P=\frac{NRT}{V}=\frac{3\times253}{303}=2.5atm$
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