College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 5 - Problems - Page 185: 9


The radius of curvature is $4762~ft$

Work Step by Step

We can convert the angle from degrees to radians: $1.2^{\circ} \times \frac{\pi~rad}{180^{\circ}} = 0.021~rad$ We can assume that the length of the arc is approximately equal to the length of the chord. We can find the radius of curvature: $\theta~r = d$ $r = \frac{d}{\theta}$ $r = \frac{100~ft}{0.021~rad}$ $r = 4762~ft$ The radius of curvature is $4762~ft$
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