## College Physics (4th Edition)

The radius of curvature is $4762~ft$
We can convert the angle from degrees to radians: $1.2^{\circ} \times \frac{\pi~rad}{180^{\circ}} = 0.021~rad$ We can assume that the length of the arc is approximately equal to the length of the chord. We can find the radius of curvature: $\theta~r = d$ $r = \frac{d}{\theta}$ $r = \frac{100~ft}{0.021~rad}$ $r = 4762~ft$ The radius of curvature is $4762~ft$