## College Physics (4th Edition)

The radial acceleration of an African baobab tree located at the equator is $3.37\times 10^{-2}~m/s^2$
Let $~~r = 6.38\times 10^6~m$ We can find the angular speed of the earth as it rotates: $\omega = \frac{\Delta \theta}{\Delta t}$ $\omega = \frac{2\pi~rad}{(24)\cdot (3600~s)}$ $\omega = 7.27\times 10^{-5}~rad/s$ We can find the radial acceleration of an African baobab tree located at the equator: $a_c = \omega^2~r$ $a_c = (7.27\times 10^{-5}~rad/s)^2~(6.38\times 10^6~m)$ $a_c = 3.37\times 10^{-2}~m/s^2$ The radial acceleration of an African baobab tree located at the equator is $3.37\times 10^{-2}~m/s^2$.