## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 5 - Problems - Page 185: 3

#### Answer

The average angular speed of the second hand on a clock is $~0.105~rad/s$ The angular displacement in $~5.0~s~$ is $~~0.525~rad$

#### Work Step by Step

We can find the average angular speed of the second hand on a clock: $\omega = \frac{\Delta \theta}{\Delta t} = \frac{2\pi~rad}{60~s} = 0.105~rad/s$ We can find the angular displacement in $5.0~s$: $\Delta \theta = \omega~t = (0.105~rad/s)(5.0~s) = 0.525~rad$

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