Answer
The average angular speed of the second hand on a clock is $~0.105~rad/s$
The angular displacement in $~5.0~s~$ is $~~0.525~rad$
Work Step by Step
We can find the average angular speed of the second hand on a clock:
$\omega = \frac{\Delta \theta}{\Delta t} = \frac{2\pi~rad}{60~s} = 0.105~rad/s$
We can find the angular displacement in $5.0~s$:
$\Delta \theta = \omega~t = (0.105~rad/s)(5.0~s) = 0.525~rad$
