College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 5 - Problems - Page 185: 10

Answer

We can rank the flywheels in order of angular speed, from largest to smallest: $c \gt d \gt a = b = e$

Work Step by Step

In general: $\omega = \frac{2\pi}{T}$ We can find the angular speed of each flywheel: (a) $\omega = \frac{2\pi}{T} = \frac{2\pi}{0.0040~s} = 1571~rad/s$ (b) $\omega = \frac{2\pi}{T} = \frac{2\pi}{0.0040~s} = 1571~rad/s$ (c) $\omega = \frac{2\pi}{T} = \frac{2\pi}{0.0010~s} = 6283~rad/s$ (d) $\omega = \frac{2\pi}{T} = \frac{2\pi}{0.0020~s} = 3142~rad/s$ (e) $\omega = \frac{2\pi}{T} = \frac{2\pi}{0.0040~s} = 1571~rad/s$ We can rank the flywheels in order of angular speed, from largest to smallest: $c \gt d \gt a = b = e$ Note that a flywheel with a longer period has a smaller angular speed.
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