## College Physics (4th Edition)

The riders move through a distance of $16.8~m$
We can convert the angle to radians: $120^{\circ}\times \frac{\pi~rad}{180^{\circ}} = \frac{2\pi}{3}~rad$ We can find the distance through which the riders move: $d = \theta~r$ $d = (\frac{2\pi}{3}~rad)(8.0~m)$ $d = 16.8~m$ The riders move through a distance of $16.8~m$