College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 26 - Problems - Page 1012: 61


$(pc)^2 = K^2+2KE_0$

Work Step by Step

We can find an expression for $(pc)^2$: $E^2 = E_0^2+(pc)^2$ $(K+E_0)^2 = E_0^2+(pc)^2$ $K^2+2KE_0+E_0^2 = E_0^2+(pc)^2$ $(pc)^2 = K^2+2KE_0$
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