Answer
$(pc)^2 = K^2+2KE_0$
Work Step by Step
We can find an expression for $(pc)^2$:
$E^2 = E_0^2+(pc)^2$
$(K+E_0)^2 = E_0^2+(pc)^2$
$K^2+2KE_0+E_0^2 = E_0^2+(pc)^2$
$(pc)^2 = K^2+2KE_0$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 26 - Problems - Page 1012: 61
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
