College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 26 - Problems - Page 1012: 53


$p = 4.9~mc$

Work Step by Step

We can find the magnitude of the momentum: $E^2 = p^2c^2+m^2c^4$ $(5.0~mc^2)^2 = p^2c^2+m^2c^4$ $25~m^2c^4 = p^2c^2+m^2c^4$ $p^2c^2 = 24~m^2c^4$ $p^2 = 24~m^2c^2$ $p = \sqrt{24}~mc$ $p = 4.9~mc$
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