College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 26 - Problems - Page 1012: 58


$1~MeV/c^2 = 1.78\times 10^{-30}~kg$

Work Step by Step

We can convert $1~MeV/c^2$ to units of $kg$: $1~MeV/c^2\times \frac{1.60\times 10^{-13}~J}{1~MeV}\times \frac{c^2}{(3.0\times 10^8~m/s)^2} = 1.78\times 10^{-30}~kg$ Therefore: $1~MeV/c^2 = 1.78\times 10^{-30}~kg$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.