## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 26 - Problems - Page 1012: 58

#### Answer

$1~MeV/c^2 = 1.78\times 10^{-30}~kg$

#### Work Step by Step

We can convert $1~MeV/c^2$ to units of $kg$: $1~MeV/c^2\times \frac{1.60\times 10^{-13}~J}{1~MeV}\times \frac{c^2}{(3.0\times 10^8~m/s)^2} = 1.78\times 10^{-30}~kg$ Therefore: $1~MeV/c^2 = 1.78\times 10^{-30}~kg$

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