## College Physics (4th Edition)

$p = 1.45~MeV/c$
$mc^2 = 0.511~MeV$ $mc = 0.511~MeV/c$ Since the total energy is 3.00 times the rest energy, the total energy $E = 3.00~mc^2$ We can find the momentum $p$: $E^2 = p^2c^2+m^2c^4$ $(3.00~mc^2)^2 = p^2c^2+m^2c^4$ $9.00~m^2c^4 = p^2c^2+m^2c^4$ $p^2c^2 = 8.00~m^2c^4$ $p^2 = 8.00~m^2c^2$ $p = \sqrt{8.00}~mc$ $p = (\sqrt{8.00})~(0.511~MeV/c)$ $p = 1.45~MeV/c$